Math, asked by rahulchakraborty227, 9 months ago

if 3^x-1 - 3^x-3 = 8, then the value of (x² – X + 4) is​

Answers

Answered by samruddhijamdade96
0

Answer:10

Step-by-step explanation:x=3

Just guessed it

Answered by qwtiger
0
Given, 3^(x-1) - 3^(x-3) = 8

we know that (a^m)/(a^n) = a^ (m-n)

3^2*{3^(x-3)} - 3^(x-3) = 8

9 * { 3^(x-3) } - 3 ^ (x-3) = 8

8 * { 3^ (x-3) } = 8

3^ (x-3) = 8/8 = 1

We know that anything power zero is 1 i.e.
a^ 0 = 1 where, a > 0


3^ (x-3) = 1

x-3 = 0

x = 3

Then, x^2 - x + 4 = 3^2 - 3 + 4
= 9 - 3 + 4 = 8

Answer is 8
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