Question

If 3^(x - 1)= 9 and 4^(y + 2) = 64, find the value of x/y​

Answer 1

Answer:

X=3and y=1

Step-by-step explanation:

3^(x-1)=9

3^(x-1)=3^2

so x-1=2

so X=3

and

4^(y+2)=64

4^(y+2)=4^3

so (y+2)=3

so y=1

Answer 2

hey mate

here is ur answer

$\Huge\orange{\boxed{\boxed{\underline{ANSWER}}}}$

$\bf given,3^{x-1}=9=>3^{x-1}=3^2$

$\bf x-1=2$

$\Huge \bf {\underline{x=3}}$

$\bf in \: the \: same \: way ,$

$\bf 4^{y+2}=64=>4^{y+2}=4^3$

$\bf y+2=3$

$\Huge \bf {\underline{y=1}}$

$\Huge \bf {\boxed {\underline{ \frac{x}{y}=3}}}$

Some more identities related:

$→a^1=a$

$→a^0=1$

$→a^m×a^n=a^{m+n}$

hope the answer helps

$\huge \pink{ \boxed{ \boxed{ \mathbb{ \mid \ulcorner THANKS \urcorner \mid }}}}$