Question

please solve physics question


find the resistance

Answer 1

R3And R4 Are in series
R34 = 2+2 = 4 ohm
R2 and R34 will be in parallel
R234 = 4×4/(4+4)= 2ohm
R1 , R234 and R5 will be in series
R12345 = 1+2+1=4ohm
and R6 and R7 are series
R67 = 2+2 = 4ohm
now
R12345 and R67 will be in parallel
Req = 4×4/(4+4) = 2 ohm

Answer 2

let R3 and R4 are in series so total resistance R'= 2 ohm
and R' a and R2 are in parallel so total resistance 1/R"= 1/4+1/4= 1/2
so R"= 2 ohm
as here R1+R"+R5 are in series so the total resistance R"'= 4 ohm
and here R6&R7 are in series so R""= 4oh
$x + y = 10 \: it \: wwd \\ \\ \\ \\ \\ \\ \:$
m
and R''"&R"' are in parallel so total resistance. 1/R= 1/4+1/4
1/R= 1/2
so R = 2