Question

If 3^x-1=9 and 4^y+2=64 ,find the value of y/x-x/y

Answer 1

I think that this is the right ans.

Answer 2

Answer:

The value is $\frac{-8}{ 3}.$

Explanation:

Given is $3^{x-1}=9$ and $4^{y+2}=64$

Find the value of $\frac{4}{x}-\frac{x}{y}$

Solution:

The given value is $3^{x-1} =9 , 4^{y+2}=64$

Now, we take  

$3^{x-1}=9\\ 3^{x-1}=3^{2}$

Compare both side, base are the same.

So,

$x-1=2\\x=3$

Again,

$y+2\\4=64\\4^{y+2}=4^3$

Compare both sides base are same

So,

$y+2=3\\y=1$

Now, $\frac{4}{x}-\frac{x}{y}$

⇒ $\frac{1}{3}-\frac{3}{1}$

$\frac{1-9}{3}=\frac{-8}{3}$

Hence, the value is $\frac{-8}{ 3}$

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