Question

If (3-x)^2-|(x-3)| – 12 = 0 then sum of real values of x is (A) 6 (B) 5 (C) 4 (D) 3​

Answer 1

Answer:

all

Step-by-step explanation:

9+x²-6x-x+3-12=0

9+3-12 will be cancelled

x²-7x=0

x(x-7) =0

x=x+7