if 3^x-3^x-1=18, find x
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For this question we need to find the value of x, it could be found by using basic algebraic rules.
3^x-3^(x-1)=18
i.e. 3^x-3^x * 3^-1=18
i.e. 3^x-(3^x/3)=18
Multiplying throughout by 3, we get,
3*3^x-(3^x)=18*3
let us substitute 3^x=m, we have,
3m-m= 54
i.e. 2m=54
i.e. m=27
Now, resubstituting, m=3^x, we have,
3^x=27
i.e. 3^x=3^3
i.e. x=3.
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