If 3+x,x-3,-2x+12 are in A.P., then value of x is:
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x+2,2x,2x+3 are in A.P.
⇒(2x)−(x+2)=(2x+3)−(2x)
2x−x−2=2x+3−2x
x−2=3
∴x=5
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