Question

if 3(y-5)-5(y-2)=0, then the value of y is ​

Answer 1

Explanation:

• First write the given equation

$\longrightarrow\sf 3 (y-5)-5 (y-2)=0$

• Simplify

$\longrightarrow\sf 3y-15-5y+10=0$

$\longrightarrow\sf 3y-5y-15+10=0$

$\longrightarrow\sf -2y-5=0$

$\longrightarrow\sf -2y=5$

$\longrightarrow\sf y=\dfrac{5}{-2}$

Answer 2

Answer:

- 2.5

Explanation:

3 ( y - 5 ) - 5 ( y - 2 ) = 0

3y - 15 - 5y + 10 = 0

3y - 5y - 15 + 10 = 0

- 2y - 5 = 0

- 2y = 5

y = 5 / - 2

= - 5 / 2

y = - 2.5