Question

If 300 √3 m high tower makes angle of elevation at a point on ground which is 300 m away from its foot, then
find the angle of elevation.​

Answer 1

Answer:

Given-

Height of the tower = 300√3m

Distance from its foot= 300m

tan theta = 300√3/300=√3

theta= 60°

Angle of elevation = 60°

Answer 2

The angle of elevation is 60°.

Given:

• If 300 √3 m high tower.
• Makes angle of elevation at a point on ground which is 300 m away from its foot.

To find:

• Find the angle of elevation.

Solution:

Concept to be used:

Draw figure and apply trigonometric ratio to find the angle.

Step 1:

According to the situation, draw the figure and label the right triangle as attached.

Step 2:

Angle of elevation can be find using tan trigonometric ratio.

$\bf tan \: \theta = \frac{ \text{\bf side \: opposite \: to \: angle}}{\text{\bf side \: adjacent \: to \: angle}}$

or

$tan \: \theta = \frac{AB}{AC}$

or

$tan \: \theta = \frac{300 \sqrt{3} }{300}$

or

$tan \: \theta = \sqrt{3}$

or

$tan \: \theta = tan \: 60 ^{ \circ}$

or

$\bf \theta = 60 ^{ \circ}$

Thus,

Angle of elevation is 60°.

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