Question

IF 300√3m HIGH TOWER MAKES ANGLE OF ELEVATION AT A POINT ON GROUND WHICH IS 300M AWAY FROM ITS FOOT THEN FIND THE ANGLE OF ELEVATION.

Answer 1

CD is the height of the flag and suppose the height of tower BC = h
Now consider right triangle ABD , we have;
tan 60° = BDAB = BD120⇒3√ = BD120⇒BD = 1203√
Also considering right triangle ABC, we have;
tan 45° = BCAB = h120⇒1 = h120⇒h = 120
So height of flag = BD - BC = 1203√−120 = 120(3√−1) = 120×0.732 = 87.84
Therefore height of the flag is 87.84 m.
The values are changed but the solution is same.
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Answer 2

60°

Step-by-step explanation:

The angle of elevation is 60°