if velocity of hydrogen molecule is 5×10^4 then what is its de Broglie wavelength in angstromes
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Lamda = h/p= h/mv
Here lamda is de broglie wavelength
So lamda = 6.62× 10^-34÷(2× 5×10^4)
= 0.662 × 10^-28 angstrom
pritomsaha26pdtw6y:
what is the mass of Hydrogen molecule
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