If 31x5 is a multiple of 3 where x is a digit, what might be the value of x.
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Answer:
x = 0, 3,6, 9
Step-by-step explanation:
According to the question,
31x5 is a multiple of 3,
Then the sum of its digits will be a multiple of 3
3 + 1 + x + 5 =3 + x
therefore, 3 + x is a multiple of 3
Then possible values of x will be,
0, 3, 6 and 9
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