if 31y5 is a multiple of 3,where y is a digit, what might be the value of z
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Answer:
The value of y might be 0 , 3 , 6 , 9 ....... etc.
Step-by-step explanation:
3 + 1 + y + 5 = 9 + y
Now the value of y must be a multiple of 3 . as it is given that the whole number (31y5) is a multiple of 3 .
Hence , the value of y = 0 , 3 , 6 , 9.......etc.
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