if 31y5 is a multiple of 3,where y is a digit what might be the value of z
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he sum of all digits of a number divisibe by 9 must be divisible by 9 itself.
Using this relation,
What is the one digit value you should put in y to make this whole thing divisible by 9?
The only answer is 1.
So now putting this value in the number abover we get 3115.
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