if 320J of heat is produced in 10s in a 2 Ω resistor find the amount of current flowing through the resistor
Answers
Answered by
6
Answer:
heat =i²rt
320=i²*2*10
320=i²*20
320/20=i²
i²=16
i=4
Explanation:
put the values in the formula of heat energy then u'll get ur answer
hope it will help you
Answered by
0
Explanation: We know
Potential difference = charge of electron/time
V = Q/t = 320/10 = 32 v
Resistance, R = 2 omega
By ohm’s law
V = IR
I = V/R
I = 32/2 = 16 A
Hence amount of current flowing through the resistor is 16 A
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