Question

If (37^3-28^3)÷(37^2+28^2+37×28)

Answer 1

Answer:

9

Step-by-step explanation:

there exists an identity such that

a^3-b^3=(a-b)(a^2+b^2+ab)

which means (a^3-b^3)÷(a^2+b^2+ab)=a-b

so putting a=37 b=28 we get 37-28=9 as the answer

Answer 2

(50653-21952)÷(1369+784+1036)

28701÷3189

9