Question

If 378 coins consist of rupee, 50 paise and 25 paise coins. whose value are proportional tp 13:11:7, the number of 50 paise coins will be

Answer 1

Let the value of rupee, 50p and 25p coins be 13x, 11x and 7x resp.

So, no. of rupee coins = 13x

no. of 50p coins = 11x ÷ 0.50 = 22x

no. of 25p coins = 7x ÷ 0.25 = 28x

So, total no. of coins we have

7x + 22x + 28x = 378

63x = 378

x = 6

So no. of 50p coins are 22x = 22 x 6 = 132 coins

Answer 2

Hello Dear.

Here is the answer---


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Given →
Total Coins = 378 coins

Let the Value of Rupee, 50 paise and 25 paise be 13x, 11x and 7x respectively.

Number of 1 Rupees coins = 13x/1
                                           =  13x

Number of 50 Paise(Rs.0.50) coins = 11x/0.50
                                             
                                                         = 22x
    
Number of 25 Paise (Rs. 0.25) coins = 7x/0.25
                                                           =28x


∴ 13x + 22x + 28x = 378
⇒ 63x = 378
⇒ x = 6

Thus, Number of Rupees Coins = 13x
                                                   = 13 × 6
                                                   = 78 coins.

Number of 50 Paise coins = 11x
                                          = 11 × 6
                                          = 66 Coins

Number of 25 paise coins = 7x
                                          = 7 × 6
                                          = 42 coins.


Thus, Number of 50 Paise Coins is 66.


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Hope it helps.

Have a Marvelous Day.