The long and short hands of a clock are 6cm and 4 cm respectively. Find the sum of distances travelled by their tips in a day.
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Short hand will rotate 2 times in a day
Distance --- 2*22/7*4*2 equal 352/7
Long hand will rotate 24 times
Distance -----2*22/7*6*24 equal 4224/7
Total distance equal 352/7 plus 4224/7 equal 653.7eprox
Distance --- 2*22/7*4*2 equal 352/7
Long hand will rotate 24 times
Distance -----2*22/7*6*24 equal 4224/7
Total distance equal 352/7 plus 4224/7 equal 653.7eprox
Answered by
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Answer:
Given :
Length of short hand = 4 cm
Length of long hand = 6 cm
We know short hand make 1 revolution in 12 hours while long hand in 1 hour.
Distance travelled by short hand in 24 hours = 2 × 2 π × 4 = 16 π cm
Distance travelled by long hand in 24 hours = 24 × 2 π × 6 = 288 π cm
Total distance travelled = 16 π cm + 288 π cm = 304 π cm
Therefore , sum of distances travelled by their tips in one day is 304 π cm.
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