Question

If 37800 = 5^a x 2^b x 3^c x 7^d
Then find a+b+c+d

Answer 1

Answer:

Step-by-step explanation:

37800 = 5^a x 2^b x 3^c x 7^d

37800=2³x3³x5²x7

5^a x 2^b x 3^c x 7^d =2³x3³x5²x7

On comparing the powers we get

a=2,b=3,c=3 and d=1

a+b+c+d=2+3+3+1

=9

Answer 2

Answer:

9

Step-by-step explanation:

Given: 37800 = 5^a x 2^b x 3^c x 7^d

To find: a+b+c+d

Solution:

According to calculation of prime factor

we get,

=> 37800 = 5² x 2³ x 3³ x 7

Taking 37800 in terms of 5^a x 2^b x 3^c x 7^d

we get,

5^a x 2^b x 3^c x 7^d =2³ x 3³ x 5² x 7

Now, Comparing the powers,

we get,

a = 2, b = 3, c = 3, d = 1

∴ a + b + c + d = 2 + 3 + 3 + 1 = 9

Hence, a + b + c + d = 9. Ans

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