Question

If (3a +1)
^2 + (b-1)^2 + (2c -3)
^2 = 0, then the value of 3a+b+2c is equal to

a) 3 b) -1 c) 2 d) 5​

Answer 1

Answer:

(3a+1)=is the second value

Step-by-step explanation:

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