Question

if 3a^2 =4a-5 and 3b^2 =4b-5 where a not equal to b , find the value of a^2 + b^2....

Answer 1

Add both equations.
3a^2+3b^2=4a-5+4b-5
3(a^2+b^2)=-10+4(a+b)
a^2+b^2=4(a+b)-10/3

Answer 2

Answer:

$(a^2+b^2) =\frac{4(a+b)-10}{3}$

Step-by-step explanation:

Given : $3a^2 =4a-5$

           $3b^2 =4b-5$

To Find :  find the value of $a^2 + b^2$

Solution:

$3a^2 =4a-5$  ---1

$3b^2 =4b-5$   ---2

Add 1 and 2

$3a^2+3b^2 =4a-5+4b-5$

$3a^2+3b^2 =4(a+b)-10$

$3(a^2+b^2) =4(a+b)-10$

$(a^2+b^2) =\frac{4(a+b)-10}{3}$

Hence $(a^2+b^2) =\frac{4(a+b)-10}{3}$