if 3a^2 =4a-5 and 3b^2 =4b-5 where a not equal to b , find the value of a^2 + b^2....
Answers
Answered by
29
Rearrange the above equations
3a^2 - 4a +, 5 = 0
3b^2 - 4b + 5 = 0
Now these are the roots of quadratic equation 3x^2- 4x + 5 = 0
Hence a and b are roots of this quadratic equation since they satisfy the above equation
So a+b = 4/3 & ab = 5/3
(a + b) ^2 - 2ab =, a^2 + b^2
= (4/3)^2 - 2(5/3)
=16/9 - 10/3
=(-14)/9
Now a^2 + b^2 is coming out to be negative becausr the roots of the equation are imaginary.
Hope it helps you
3a^2 - 4a +, 5 = 0
3b^2 - 4b + 5 = 0
Now these are the roots of quadratic equation 3x^2- 4x + 5 = 0
Hence a and b are roots of this quadratic equation since they satisfy the above equation
So a+b = 4/3 & ab = 5/3
(a + b) ^2 - 2ab =, a^2 + b^2
= (4/3)^2 - 2(5/3)
=16/9 - 10/3
=(-14)/9
Now a^2 + b^2 is coming out to be negative becausr the roots of the equation are imaginary.
Hope it helps you
Answered by
3
Answer:
Step-by-step explanation:
3a+2b=1 ..... (1)
-2a+3b=0.....(2) solve equation please
Similar questions