Question

If 3A=2B=5C find A:B:C.Emergency case pls pls​

Answer 1

Answer:

Taking the LCM of 3 , 2 & 5 , we get 30 .

Therefore,

30A10=30B15=30C6

Dividing all by 30 , we get,

A10=B15=C6=k (say)

A10 =k

=>A=10k

B15 =k

=>B=15k

C6 =k

=>C=6k

Now,

A:B:C=10k:15k:6k

Removing k ,

A:B:C=10:15:6