If 3A=2B=5C,then find A:B:C.
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Let 3A = 2B = 5C = x
so, 3A = x
=> A = x/3
similarly, B = x/2 and C = x/5
then..........A:B:C = x/3 : x/2 : x/5 {LCM of 3,2,5 = 30 }
= 1/3 : 1/2 : 1/5
= 1/3 * 30 : 1/2 * 30 : 1/5 * 30
= 10 : 15 : 6
so, 3A = x
=> A = x/3
similarly, B = x/2 and C = x/5
then..........A:B:C = x/3 : x/2 : x/5 {LCM of 3,2,5 = 30 }
= 1/3 : 1/2 : 1/5
= 1/3 * 30 : 1/2 * 30 : 1/5 * 30
= 10 : 15 : 6
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