Math, asked by pushkar635, 9 months ago

if 3a+ 2b + c= 22,b+c = 8 and c= 6, what is the value of a +b+c?​

Answers

Answered by foodwrap50
3

Answer:

12

Step-by-step explanation:

b+c=8

c=6

so,

b+6=8

so, b=2

now, 3a +(2×2)+6=22

so, 3a +10=22

3a=12

a=12÷3

=4

a+b+c=2+4+6=12

Answered by gms142
0

Answer:

given that,3a+2b+c =22

c+b=8

c=6

so that, b=2

substitute b and c in 3a+2b+c =22

so we get a= 4

a+b+c=4+2+6

=12

Similar questions