Question

If 3A=4B=6C; find: A:B:C.

Answer 1

let 3A =4B =6C be x
then A =x/3
then B =x/4
then C =x/6
Therefore, A:B:C = x/3 : x/4:x/6
= 1/3:1/4:1/6
= 1/3*12: 1/4*12: 1/6*12
= 4:3:2[L.C.M of 3,4,6 is 12]

Answer 2

Step-by-step explanation:

let 3A=4B=6C,be x

A=x/3 ,B=x/4 ,C=x/6

therefore of A:B:C =x/3 :x4 :x/6

then take x as 1

=1/3 :1/4 :1/6

take L.C.M of 3,4,6 that is =12

to make the denominator equal multiply it to all ratios and multiply to both numerator and denominator

It becomes=1/3*4 :1/4*3 :1/6*2

=4/12 :3/12 :2/12

therefore the ratio of A:B:C = 4:3:2

Ans = 4:3:2