Math, asked by kshitij001, 4 months ago

If 3a + 4b =9 and ab =2, find the value of 27 a3 + 64 b3 ​

Answers

Answered by bhatbhargavi06
2

Answer:

27a³+64b³= 81

Step-by-step explanation:

3a+4b=9 (Given)

ab=2

(3a+4b)³= 27a³+64b³+3×3a×4b(3a+4b)

9³= 27a³+64b³+ 36ab×9 Since (3a+4b=9)

729=27a³+64b³+ 36×2×9 Since(ab=2)

729=27a³+64b³+648

729-648=27a³+64b³

27a³+64b³= 81

Please mark as brainliest.

Similar questions