If 3a + 4b =9 and ab =2, find the value of 27 a3 + 64 b3
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Answer:
27a³+64b³= 81
Step-by-step explanation:
3a+4b=9 (Given)
ab=2
(3a+4b)³= 27a³+64b³+3×3a×4b(3a+4b)
9³= 27a³+64b³+ 36ab×9 Since (3a+4b=9)
729=27a³+64b³+ 36×2×9 Since(ab=2)
729=27a³+64b³+648
729-648=27a³+64b³
27a³+64b³= 81
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