Question

If 3a - b+c=0, prove that 9a2 – b2+ c2 + 6ac=0.​

Answer 1

Answer:

Answer will be = 3

Step-by-step explanation:

a+b+c=0

so, a3 + b3 + c3 =3abc

now,a2/bc +b2/ac +c2/ab=a3+ b3+ c3/abc

=3abc/abc

=3

Answer 2

72 = 72

96 = 96

first 69 and second 27 = 6927

58 × 87 = 58 × 85.

87 × 78

first 78 and second 85 = 7885

then. 79 × 86

•°• ANSWER = 6897

this helps you please make my answer brainliest.

Answer 3

72 = 72

96 = 96

first 69 and second 27 = 6927

58 × 87 = 58 × 85.

87 × 78

first 78 and second 85 = 7885

then. 79 × 86

•°• ANSWER = 6897

this helps you please make my answer brainliest.

Answer 4

72 = 72

96 = 96

first 69 and second 27 = 6927

58 × 87 = 58 × 85.

87 × 78

first 78 and second 85 = 7885

then. 79 × 86

•°• ANSWER = 6897

this helps you please make my answer brainliest.