Math, asked by ajmalchalil9131, 18 hours ago

if 3asquare+2bsquare/2bsquare-asquare=15/7 and a square : b square =m:n , then m-n=

Answers

Answered by senboni123456
1

Answer:

Step-by-step explanation:

We have,

\sf{\dfrac{3\,a^{2}+2\,b^2 }{2\,b^2-a^2}=\dfrac{15}{7}}

Applying componendo and dividendo,

\sf{\dfrac{3\,a^{2}+2\,b^2+2\,b^2-a^2 }{3\,a^{2}+2\,b^2-2\,b^2+a^2}=\dfrac{15}{7}}

\sf{\implies\,\dfrac{2\,a^{2}+4\,b^2 }{4\,a^{2}}=\dfrac{15}{7}}

\sf{\implies\,\dfrac{a^{2}+2\,b^2 }{2\,a^{2}}=\dfrac{15}{7}}

\sf{\implies\,7\,a^{2}+14\,b^2= 30\,a^{2}}

\sf{\implies\,14\,b^2= 23\,a^{2}}

\sf{\implies\dfrac{a^{2}}{b^2}=\dfrac{14}{ 23}}

But given that, \sf{\dfrac{a^2}{b^2}=\dfrac{m}{n}}

So,

\sf{\implies\dfrac{m}{n}=\dfrac{14}{ 23}}

\sf{\implies\,m-n=14- 23=-9}

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