Question

if 3cotA=2 then find the value of 4sinA-3cosA/2sinA+3cosA​

Answer 1

Answer:

if 3cotA=2

then

cotA=2/3

sinA=3 as cotA=cosA/sinA

cosA=2

substituting the values in 4sinA-3cosA/2sinA+3cosA

=4×3-3×2/2×3+3×2

=12-6/6+6

=6/12

=1/6 (Answer)

Answer 2

Answer:

gokul paithayamaa illaya

Step-by-step explanation:

1. avan Nichamaa Oru
2. kandipa Avan Mental dha
3. No doubt
4. kandipa avan paithiyam dha confirm No doubt there