If 3m – 5n = – 1 and 2m = n – 3, find the values of (3m + 5n) and (m + 2n).
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Solution
3m-5n+1 = 0. (1)
2m- n+3 = 0. (2)
(1) multiply by 2. 6m-10n+2 = 0
(2) multiply by 3. 6m- 3n+9 = 0
-7n-7 = 0
n = -1
substitute in (1),
3m-5(-1)+1 = 0.
3m = -6
m = -2
3m + 5n = 3(-2)+5(-1) = -6-5 = -11
m+2n = -2+2(-1) = -2-2 = -4
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