Math, asked by lalitkumar1236, 1 year ago

If 3pumps can empty a cistern in 2days by working 8hours a day ,then how many hours day must 4 pumps work to empty a cistern in one day?

Answers

Answered by VijayL
2
no. of pumps. hours
3. 8×2=16
4. x hours

inversely proportional......
so


3×16. = 4×x
3×4=x

x=12 hours




hope this helps.....
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