Question

If 3rd term of an Ap is 13 and 6 th term isn28 find its 50 th term
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Answer 1

Answer:

the 50th term is 248

Step-by-step explanation:

3rd term is 13 (formula is a+(n-1)d)

a+2d =13............equation no. 1

6th term is 28 (same formula)

a +5d=28...........equation no.2

from eq. 1 and 2 we'll get...

a+2d=13

a+5d=28

- - -

_______

- 3d=-15

d=5

putting the value of d in eq no. 1 (u can put it in any eq.)

a+2d=13

a+2*5=13

a=13-10

a=3

50th term (n=50)

formula is :

an=a+(n-1)d

an=3+(50-1)5

an=3+49*5

an=3+245

an=248

50th term is 248. (ur answer )

hope it helps you...

Answer 2

Given:

t3=13....... (1)

t6=28......... (2)

To find:

t50=?

Solution:

tn=a+(n-1) d........ (Formula)

t3=a+(3-1) d

13=a+2d.........(From (1))

t6=a+(6-1) d

28=a+5d.........(From(2))

Subtracting equation. (1) from (2) we get,

3d=15

d=15/3

d=5

Substitution the value of d in (1) we get,

13=a+2d........(1)

13=a+2×5

13=a+10

a=13-10

a=3

Now, 50 th term

According to the formula,

t50=3+(50-1) 5

t50=3+49×5

t50=3+245

t50=248

Therefore, The 50 th term of an Ap is 248

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