If 3sinθ - 4cosθ = 0 , then the value of 3sinθ + 4cosθ is
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Answer:
3sinθ-4cosθ=0
3sinθ=4cosθ
sinθ/cosθ=4/3
tanθ=4/3
and 3sinθ+4cosθ
divide 3sinθ+4cosθ by cosθ
we get
3sinθ/cosθ + 4cosθ/cosθ
=3tanθ + 4
=3×4/3 +4
=4+4
=8
hence the correct answer is 8
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༒ Question ➽
If θ is Acute angle and 3sinθ = 4cosθ then Find out the value of 4sin2θ - 3cos2θ + 2.
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༒ Given ➽
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༒ To Find ➽
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༒ Solution ➽
As
So,
Hence,
So,
As θ is Acute so sinθ will not negative
Hence,
Now,
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༒ Alernate Solution ➽
As
Squaring We get
We Know
Now,
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