If 3sin theta + 5 cos theta = 5 . prove that 5 sin theta- 3 cos theta = +- 3
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Step-by-step explanation:
Given 3sinθ+5cosθ=5
Let 5sinθ−3cosθ=x
Squaring on both sides for both the equations
⇒9sin
2
θ+25cos
2
θ+30sinθcosθ=25
⇒25sin
2
θ+9cos
2
θ−30sinθcosθ=x
2
Adding the equations ;
⇒34(sin
2
θ+cos
2
θ)=25+x
2
⇒x
2
=34−25=9
⇒x=±3
∴5sinθ−3cosθ=±3
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