Question

if √3sin theta-cos theta=0 then prove that tan 2 theta =2 tan theta/1-tan ^theta​

Answer 1

Answer:

IVU, Find the LCM of the following set of the numbers by the common division method. b) 25, 45, 30 ​

Answer 2

Step-by-step explanation:

given

√3sin theta-cos theta=0

to prove

tan 2 theta =2 tan theta/1-tan ^theta

Tan 2theta = sin 2theta / Cos 2theta

Tan 2theta =Sin 2theta ÷ cos 2theta

Tan 2theta =Sin 2theta ÷ 1 - Tan^2 theta / 1 + Tan^2 theta

we know that.

Sin 2theta = 2 Tan theta / 1 + tan^2 theta

Cis 2theta = 1 - Tan^2 theta / 1 + Tan^2 theta

now

Tan 2theta = ( 2 Tan theta / 1 + tan^2 theta ) ÷ ( 1 - Tan^2 theta / 1 + Tan^2 theta )

= 2 Tan theta / 1 - Tan^2 theta.

hence proved

additional

√3 Sin theta - cos theta =0

√3 sin theta = cos theta

sin theta = ( 1/ √3 ) cos theta

√3 Tan theta = 1

Tan theta = 1/√3

theta = 30°