if 3sinA=5sinB then tan A+B/2/tan A-B/2=?
Attachments:
Answers
Answered by
22
sinA/sinB=5/3
(sinA + sinB)/(sinA-sinB)=8/2=4
2sin((A+B)/2)*cos((A-B)/2)/2cos((A+B)/2)sin((A-B)/2)=4
tan((A+B)/2)/tan((A-B)/2)=4
(sinA + sinB)/(sinA-sinB)=8/2=4
2sin((A+B)/2)*cos((A-B)/2)/2cos((A+B)/2)sin((A-B)/2)=4
tan((A+B)/2)/tan((A-B)/2)=4
Similar questions