One angle of a triangle is 75^. Find the remainig two angle if there is difference 35^.
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Angle sum property of a Δle = 180°
∴ x+y+z=180°
Given one angle is 75, x=75°.
y-z=35°(Given)
∴y=35°+z → 1
Substituting in 1, we get:
x+y+z=180°
75°+35°+z+z=180°
110°+2z=180°
2z=180°-110°
z=70°÷2
⇒z=35°
Substituting z in 1, we get:
y=35°+z
=35°+35°
∴y=70°
∴The angles are 75°, 35° and 70°.
∴ x+y+z=180°
Given one angle is 75, x=75°.
y-z=35°(Given)
∴y=35°+z → 1
Substituting in 1, we get:
x+y+z=180°
75°+35°+z+z=180°
110°+2z=180°
2z=180°-110°
z=70°÷2
⇒z=35°
Substituting z in 1, we get:
y=35°+z
=35°+35°
∴y=70°
∴The angles are 75°, 35° and 70°.
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