if 3tan =4 then prove that root sec a-cosec a upon root sec a +cosec a is equal to 1upon root 3
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3tan a =4
tan a =4/3 = Perpendicular /base
(H Sq.) =(P Sq.) +(B Sq.)
=( 4 sq.) +(3 sq.)
= 16 + 9
(H sq.) = 25
(H) = 5
Sec a=H/B =5/3
Cosec a=H/B=5/4
=Root sec a - Cosec a/root sec a +Cosec a
=root 5/3-5/4 / 5/3+5/4
=root 5/12 /root 35/12
=1 root 7
tan a =4/3 = Perpendicular /base
(H Sq.) =(P Sq.) +(B Sq.)
=( 4 sq.) +(3 sq.)
= 16 + 9
(H sq.) = 25
(H) = 5
Sec a=H/B =5/3
Cosec a=H/B=5/4
=Root sec a - Cosec a/root sec a +Cosec a
=root 5/3-5/4 / 5/3+5/4
=root 5/12 /root 35/12
=1 root 7
Avi11111111:
hey, check out the answer for your question. instead of 1 root 3 it is coming 1 root 7
even I am getting the same answer but its a board question paper.
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please like, and mark as brainlist answer if you want centum in 10 th board.
please mark as brainlist answer
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