Question

IF 3tanA=4,then find sinA and cosA​

Answer 1

Answer:

1. Tan=4/3
2. Tan=P/B
3. H²=P²+B²
4. H²=4²+3²
5. H²=16+09
6. H= √25
7. H=5
8. SO, SinA=P/H
9. SinA=4/5
10. CosA=B/H
11. CosA=3/5

Answer 2

Note: don't comment on my drawing

3tanA=4

tanA=4/3

tan A= BC/AB

by Pythagoras theorem

AC^2=BC^2+AB^2

AC^2=(4)^2+(3)^2

AC^2=16+9

AC^2=25

AC=√25

AC=5

Now,

AC=5,BC=4,AB=3

so as we know that,

sin=P/H=4/5

cosA=B/H=3/5

hope it will help you and mark me as brainliest.