If 3tanA=4,then find sinA and cosA.
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Answered by
1
Answer:
step by step explanation ☝️
Step-by-step explanation:
Let ABC is a right angle triangle
3tanA=4 ⇒tanA=
3
4
=
AB
BC
By using Pythagoras theorem
AC
2
=AB
2
+BC
2
=(3)
2
+(4)
2
=9+16=25
∴AC=
25
=5
sinA=
Hypotenuse
Opposite side of∠A
=
AC
BC
=
5
4
∴cosA=
Hypotenuse
Adjacent side of∠A
=
AC
AB
=
5
3
∴sinA=
5
4
and cosA=
5
4
please mark me as BRAIN LIST
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Answered by
0
Answer:
3tanA=4
tanA=4/3
see above figure
from Pythagoras triplets hypotenuse =5
so sinA=4/5
cosA=3/5
hope you understand mate
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