Question

If 3tanA = 4, then the value of
3 sinA+2cos A/3sin A-2cos A
is
(a) 1
(b) 7/25
(C) 3
(d) none of these

Answer 1

Answer:

3tanA = 4

tanA = 4 ÷ 3

This , 3sinA+2cosA ÷ 3sinA-2cosA

= 3tanA+2 ÷ 3tanA-2

= 3×4÷3+2/3×4÷3-2

=6÷2

= 3

Answer 2

$answer$.

$3 \tan( = 4)$

$\tan(a = 4 \div 3)$

$this \: 3 \sin(a + 2 \cos(a) )$

$= 3 \tan(a + 2 = 3 \tan(a - 2) )$

$= 3 \times 4 \div 3 + 2 \div 3 \times 4 \div 3 - 2$

$6 \div 2$

$= 3$

Hope it will help you.