If √3tanØ=3SinØ find the value of sin²Ø-Cos²ø
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Answer:
We have,
3
tanθ=3sinθ
3
cosθ
sinθ
=3sinθ
3
sinθ
sinθ
=3cosθ
3
1
=cosθ
On squaring both side, we get
3
1
=cos
2
θ........(1)
1−sin
2
θ=
3
1
sin
2
θ=1−
3
1
sin
2
θ=
3
2
.........(2)
sinθ=±
3
2
Hence, this is the answer.
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