Question

If √3tanQ = 3 sinQ, find the value of sin²Q - cos²Q

Answer 1

Answer:tanA/sinA=3/√3

(sinA/cosA)(1/sinA)=√3

1/cosA=√3

cosA=1/√3

sin^2A-cos^2A

1-cos^2A-cos^2A

1-2cos^2A

1-2(1/√3)^2

1-2(1/3)

1-2/3

1/3

Answer 2

Step-by-step explanation:

the answer is in the picture