Question

If 3x + 1 ÷ x = 6 , then find 9x² + 1 ÷ x². Please someone solve me this question.

Answer 1

Answer:-

3x + 1 / x = 6

First we have to find the value of x

6x = 3x + 1

6x - 3x = 1

3x = 1

x = 1/3

Put the value of x in the second equation,

9x² + 1 / x²

= 9(1/3)² + 1 / (1/3)²

= 9 * 1/9 + 1 / 1/9

= 1 + 1 / 1/9

= 2 / 1/9

= 9 * 2

= 18

Answer 2

Answer:

the answer is 30

Step-by-step explanation:

3x+1/ₓ = 6

by squaring both sides

(3x+1/ₓ)² = 6²

9x²+1/ₓ² +2*3x*1/ₓ = 36

9x²+1/ₓ² +2*3*1 =36

9x²+1/ₓ² +6 =36

9x²+1/ₓ² = 36-6

9x²+1/ₓ²  = 30