if (3x-2) is a factor of 3xcube - Kxsquare +21x-10, find the value of K
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Answered by
2
Hey!!!!
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Given
=> (3x - 2) is a factor of 3x³ - kx² + 21x - 10
Thus => 3x - 2 = 0
=> x = 2/3 is a Zero of the polynomial
=> 3(2/3)³ - k(2/3)² + 21(2/3) - 10 = 0
=> 3(8/27) - 4k/9 + 14 - 10 = 0
=> 8/9 - 4k/9 + 4 = 0
=> (8 - 4k)/9 = -4
=> 8 - 4k = -36
=> k = 44/4
=> k = 11
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Hope this helps you
__________
Given
=> (3x - 2) is a factor of 3x³ - kx² + 21x - 10
Thus => 3x - 2 = 0
=> x = 2/3 is a Zero of the polynomial
=> 3(2/3)³ - k(2/3)² + 21(2/3) - 10 = 0
=> 3(8/27) - 4k/9 + 14 - 10 = 0
=> 8/9 - 4k/9 + 4 = 0
=> (8 - 4k)/9 = -4
=> 8 - 4k = -36
=> k = 44/4
=> k = 11
____
Hope this helps you
raj1099:
wrong answer
yes
answer is 11
yes my answer is incorrect sorry
Answered by
2
HELLO : )
GIVEN POLYNOMIAL IS 3x³ - kx² + 21x - 10
FACTOR = (3X-2)
(3x-2) = 0 ⇒ x = 2/3
SUBSTITUTING x= 2/3 IN THE POLYNOMIAL
3(2/3)³ - K(2/3)² + 21(2/3) -10 = 0
3(8/27) - k(4/9) + 21(2/3) - 10 = 0
8/9 - k (4/9) + 7(2) - 10 = 0
8/9 + 14 - 10 = k(4/9)
8/9 + 4 = 4k/9
(8+36)/9 = 4k/9
cancelling '9' on both sides.............
44 = 4k
44/4 = k
⇒k= 11
GIVEN POLYNOMIAL IS 3x³ - kx² + 21x - 10
FACTOR = (3X-2)
(3x-2) = 0 ⇒ x = 2/3
SUBSTITUTING x= 2/3 IN THE POLYNOMIAL
3(2/3)³ - K(2/3)² + 21(2/3) -10 = 0
3(8/27) - k(4/9) + 21(2/3) - 10 = 0
8/9 - k (4/9) + 7(2) - 10 = 0
8/9 + 14 - 10 = k(4/9)
8/9 + 4 = 4k/9
(8+36)/9 = 4k/9
cancelling '9' on both sides.............
44 = 4k
44/4 = k
⇒k= 11
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