Question

if 3x+2/x=7 then (9x^2-4/x^2)

Answer 1

3x+2/x-7=0
3x^2+2-7x=0
3x^2-7x+2=0
3x^2-6x-x+2=0
3x(x-2)-1(x-2)=0
(3x-1)(x-2)=0
3x-1=0
x=1/3.......i
x-2=0
x=2.......ii
putting I
9x^2-4/x^2
9×1/9-4/1/9
1-36
-35

putting ii
9×4-4/4
36-1
35

since when we put i we get answer in negative so it is neglected

hence ii will be the ans

HOPE It Helps U.....

Answer 2

Answer:

Step-by-step explanation:

3x+2/x-7=0

3x^2+2-7x=0

3x^2-7x+2=0

3x^2-6x-x+2=0

3x(x-2)-1(x-2)=0

(3x-1)(x-2)=0

3x-1=0

x=1/3.......i

x-2=0

x=2.......ii

putting I

9x^2-4/x^2

9×1/9-4/1/9

1-36

-35

putting ii

9×4-4/4

36-1

35

since when we put i we get answer in negative so it is neglected

hence ii will be the ans

HOPE It Helps U.....