Question

If 3x-2y=11 and xy=12, find the value of 27x^3-8y^3

Answer 1

Hey mate,☺️☺️
Here is your answer☺️☺️


a3-b3=(a-b) (a2+ab+b2)

(3x)3-(2y)3= (3x-2y) (9x2+4y2+6xy)

=11(9x2+4y2-12xy+18xy)

=11((3x-2y)2+18xy)

=11(121+18*12)

=11(121+216)

=11*337

=3707

Hope it helps you a lot in your future☺️☺️

THANK YOU FRIEND☺️☺️☺️

Answer 2

Hope u like my process
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Formula to be used ::
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=> a³ - b³ = (a-b)³ + 3ab(a-b)
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Given
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3x - 2y =11 and xy = 12

$27 {x}^{3} - 8 {y}^{3} \\ \\ = {(3x)}^{3} - {(2y)}^{3} \\ \\ = {(3x - 2y)}^{3} + 3 \times 3x \times 2y \times (3x - 2y) \\ \\ = {(11)}^{3} + 18xy(11) \\ \\ = 1331 + 18 \times 12 \times 11 \\ \\ = 1331 + 2376 \\ \\ = 3707$

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