if 3x+ 2y = 12 and xy = 12 find the value of 9x^2 + 4y^2
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2
3x+2y=12
(3x+2y)^2=12^2
(3x)^2+(2y)^2+2*3*2xy=144
9x^2+4y^2+12*12=144
9x^2+4y^2=144-144=0
(3x+2y)^2=12^2
(3x)^2+(2y)^2+2*3*2xy=144
9x^2+4y^2+12*12=144
9x^2+4y^2=144-144=0
abhinavmathsscience:
in which class are u
8 class
thats great I m also in 8 class.
u are from
I am from delhi
okk
and u?
ambala
Above solution is wrong brother..pls check it
thanks
Answered by
2
3x+2y=12,xy=12
squaring both sides
(3x+2y)^2=(12)^2
9x^2+4y^2+12xy=144
9x^2+4y^2+12(12)=144
9x^2+4y^2=144-144
9x^2+4y^2=0
squaring both sides
(3x+2y)^2=(12)^2
9x^2+4y^2+12xy=144
9x^2+4y^2+12(12)=144
9x^2+4y^2=144-144
9x^2+4y^2=0
hello
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