if 3x+2y=12 and xy=6,find the value of 9x^+4y^2?
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(3x+2y)^2=12^2
3x^2+2y^2+2×3x×2y = 12^2
9x^2+4x^2+12×6= 144
9x^2+4x^2=144 - 72
=72
3x^2+2y^2+2×3x×2y = 12^2
9x^2+4x^2+12×6= 144
9x^2+4x^2=144 - 72
=72
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